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★ UGC NET Paper-I · Mathematical Aptitude

Simple & Compound Interest

Complete tutorial: Simple Interest (SI), Compound Interest (CI), difference between SI and CI, formulae, half-yearly/quarterly compounding, practice questions for UGC NET Paper-1.

1

Meaning of Interest — ब्याज का अर्थ

Interest वह extra money है जो borrower lender को principal amount (मूलधन) के उपयोग के बदले में देता है।

  • Principal (P) — मूलधन: वह मूल राशि जो उधार ली/जमा की जाती है।
  • Rate (R) — दर: प्रति वर्ष प्रतिशत ब्याज दर।
  • Time (T) — समय: वह अवधि जिसके लिए पैसा उधार लिया/जमा किया जाता है।
  • Amount (A) — मिश्रधन: Principal + Interest (A = P + I)

Two Types of Interest:

  • Simple Interest (SI) — साधारण ब्याज: Interest केवल Principal पर calculate होता है।
  • Compound Interest (CI) — चक्रवृद्धि ब्याज: Interest Principal + accrued interest पर calculate होता है।
2

Simple Interest — साधारण ब्याज

Simple Interest वह ब्याज है जो केवल Original Principal पर calculate होता है, न कि पहले accrued interest पर।

SI = (P × R × T) / 100

Key Points:

  • Interest हर साल same रहता है (constant) — जब तक P, R, T same हैं।
  • Principal constant रहता है।
  • Amount = P + SI

Example:

  • Principal = ₹1000, Rate = 10% p.a., Time = 3 years
  • SI = (1000 × 10 × 3) / 100 = ₹300
  • Amount = 1000 + 300 = ₹1300
3

Simple Interest Formulae — साधारण ब्याज सूत्र

SI = (P × R × T) / 100
  • To find P: P = (SI × 100) / (R × T)
  • To find R: R = (SI × 100) / (P × T)
  • To find T: T = (SI × 100) / (P × R)
  • Amount: A = P + SI = P × (1 + RT/100)

Example 1: SI = ₹300, R = 10%, T = 3 years, find P.

  • P = (300 × 100) / (10 × 3) = 30000/30 = ₹1000

Example 2: P = ₹2000, R = 8%, T = 2 years, find SI and Amount.

  • SI = (2000 × 8 × 2) / 100 = ₹320
  • A = 2000 + 320 = ₹2320
4

Compound Interest — चक्रवृद्धि ब्याज

Compound Interest वह ब्याज है जो Principal + previously earned interest पर calculate होता है। इसे "interest on interest" भी कहा जाता है।

A = P × (1 + R/100)ⁿ (Annual Compounding)
CI = A − P

Key Points:

  • Interest हर साल increasing होता है।
  • Principal changes each year (P + interest).
  • CI हमेशा same time/rate पर SI से greater होता है (for T > 1 year).

Example:

  • Principal = ₹1000, Rate = 10% p.a., Time = 3 years
  • A = 1000 × (1 + 10/100)³ = 1000 × (1.1)³ = 1000 × 1.331 = ₹1331
  • CI = 1331 − 1000 = ₹331
  • SI = ₹300 (comparison: CI > SI)
5

Compound Interest Formulae — चक्रवृद्धि ब्याज सूत्र

A = P × (1 + R/100)ⁿ
CI = A − P = P × [(1 + R/100)ⁿ − 1]
  • To find P: P = A / (1 + R/100)ⁿ
  • To find R: R = 100 × [(A/P)¹⁄ⁿ − 1]
  • To find n: n = log(A/P) / log(1 + R/100)

Example: A = ₹1331, R = 10%, n = 3 years, find P.

  • P = 1331 / (1.1)³ = 1331 / 1.331 = ₹1000

Important: For Compound Interest, always calculate Amount first, then CI = A − P.

6

Half-Yearly & Quarterly Compounding — अर्धवार्षिक एवं त्रैमासिक चक्रवृद्धि

When interest is compounded more than once in a year:

  • Half-Yearly Compounding: Rate = R/2, Time = 2n (n = number of years)
  • Quarterly Compounding: Rate = R/4, Time = 4n
  • Monthly Compounding: Rate = R/12, Time = 12n
A = P × (1 + r/m)ⁿᵐ

Where m = number of compounding periods per year.

Example 1 (Half-Yearly): P = ₹1000, R = 10% p.a., n = 2 years, compounded half-yearly.

  • Rate = 10/2 = 5% per half-year, Time = 2×2 = 4 half-years
  • A = 1000 × (1 + 5/100)⁴ = 1000 × (1.05)⁴ = 1000 × 1.2155 = ₹1215.50

Example 2 (Quarterly): P = ₹1000, R = 12% p.a., n = 1 year, compounded quarterly.

  • Rate = 12/4 = 3% per quarter, Time = 1×4 = 4 quarters
  • A = 1000 × (1 + 3/100)⁴ = 1000 × (1.03)⁴ = ₹1125.51
7

SI vs CI — साधारण एवं चक्रवृद्धि ब्याज में अंतर

BasisSimple Interest (SI)Compound Interest (CI)
Calculation BaseOnly PrincipalPrincipal + Accrued Interest
Growth PatternLinear (constant each year)Exponential (increasing each year)
PrincipalConstantChanges (increases each year)
Amount FormulaA = P(1 + RT/100)A = P(1 + R/100)ⁿ
For T=1 yearSI = CICI = SI
For T > 1 yearSI < CICI > SI
For T < 1 yearSI > CICI < SI
8

Difference between SI & CI — SI और CI में अंतर

For 2 years:

Difference (CI − SI) = P × (R/100)²

For 3 years:

Difference (CI − SI) = P × (R/100)² × (300 + R)/100

Example: P = ₹1000, R = 10%, T = 2 years

  • SI = (1000 × 10 × 2)/100 = ₹200
  • CI = 1000 × [(1.1)² − 1] = 1000 × 0.21 = ₹210
  • Difference = ₹10
  • Formula: 1000 × (10/100)² = 1000 × 0.01 = ₹10 ✓
9

Formulae Summary — सूत्र सारांश

  • Simple Interest: SI = (P × R × T) / 100
  • SI Amount: A = P + SI = P × (1 + RT/100)
  • Compound Interest (Annual): A = P × (1 + R/100)ⁿ
  • CI: CI = A − P = P × [(1 + R/100)ⁿ − 1]
  • Half-Yearly: A = P × (1 + R/200)²ⁿ
  • Quarterly: A = P × (1 + R/400)⁴ⁿ
  • CI − SI (2 years): P × (R/100)²
  • CI − SI (3 years): P × (R/100)² × (300 + R)/100
10

Common Exam Traps — सामान्य परीक्षा जाल

  • Trap 1: For T=1 year, SI = CI → True. For T>1, CI > SI.
  • Trap 2: Half-yearly compounding: don't forget to adjust both Rate (R/2) and Time (2n).
  • Trap 3: CI formula: A = P(1 + R/100)ⁿ — always calculate Amount first, then CI = A − P.
  • Trap 4: Difference formula for 2 years: P × (R/100)² — not P × R²/100.
  • Trap 5: Simple Interest: Principal remains constant — don't add interest to principal.
  • Trap 6: Rate और Time की units match होनी चाहिए — if time is in months, convert to years.
11

Practice Questions — अभ्यास प्रश्न

Question 1 (Simple Interest)

Find the simple interest on ₹5000 at 8% p.a. for 3 years.

  • A. ₹1000
  • B. ₹1200
  • C. ₹1500
  • D. ₹1800
Answer: B. ₹1200

Explanation: SI = (5000 × 8 × 3)/100 = ₹1200.

Question 2 (Compound Interest)

Find the compound interest on ₹5000 at 10% p.a. for 2 years (compounded annually).

  • A. ₹1000
  • B. ₹1025
  • C. ₹1050
  • D. ₹1100
Answer: C. ₹1050

Explanation: A = 5000 × (1.1)² = 5000 × 1.21 = ₹6050; CI = 6050 − 5000 = ₹1050.

Question 3 (Half-Yearly Compounding)

Find the amount on ₹2000 at 10% p.a. for 1 year, compounded half-yearly.

  • A. ₹2100
  • B. ₹2150
  • C. ₹2200
  • D. ₹2205
Answer: D. ₹2205

Explanation: Rate = 10/2 = 5%, Time = 2 half-years; A = 2000 × (1.05)² = 2000 × 1.1025 = ₹2205.

Question 4 (SI vs CI Difference)

The difference between CI and SI on ₹10000 for 2 years at 10% p.a. is:

  • A. ₹50
  • B. ₹100
  • C. ₹150
  • D. ₹200
Answer: B. ₹100

Explanation: Difference = P × (R/100)² = 10000 × (10/100)² = 10000 × 0.01 = ₹100.

Question 5 (Finding Principal from CI)

At 10% p.a., the amount after 2 years (compounded annually) is ₹12100. Find the principal.

  • A. ₹9000
  • B. ₹10000
  • C. ₹11000
  • D. ₹12000
Answer: B. ₹10000

Explanation: P = A / (1.1)² = 12100 / 1.21 = ₹10000.

Question 6 (Quarterly Compounding)

Find the amount on ₹10000 at 12% p.a. for 1 year, compounded quarterly.

  • A. ₹11200
  • B. ₹11250
  • C. ₹11255
  • D. ₹11300
Answer: C. ₹11255

Explanation: Rate = 12/4 = 3%, Time = 4 quarters; A = 10000 × (1.03)⁴ = 10000 × 1.1255 = ₹11255.

12

One-Page Revision — एक पेज में पुनरावृत्ति

SI = (P × R × T) / 100 | CI = P × [(1 + R/100)ⁿ − 1]

Key Formulae:

  • SI = (P×R×T)/100
  • A (SI) = P + SI = P(1 + RT/100)
  • A (CI) = P(1 + R/100)ⁿ
  • CI = A − P

Compounding Periods:

  • Half-Yearly: R/2, 2n
  • Quarterly: R/4, 4n
  • Monthly: R/12, 12n

SI vs CI:

  • T=1: SI = CI
  • T>1: CI > SI
  • T<1: SI > CI

Difference Formulae:

  • 2 years: P × (R/100)²
  • 3 years: P × (R/100)² × (300+R)/100

Exam Formula:

SI = Simple & Constant | CI = Interest on Interest (Exponential)

UGC NET में Simple & Compound Interest के questions formula-based और application-based होते हैं। Compounding periods और SI-CI difference पर विशेष ध्यान दें।

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